argmax(T.a : number, T.b : ‘b) 🡒 ‘b, aggregator
Returns the paired value associated with the highest number. The aggregator takes two arguments. The first argument is the number used for the ordering. The second argument is the paired valued, one of them being returned.
table T = with [| as A, as B |] [| 2, "c" |] [| 0, "a" |] [| 1, "b" |] V = argmax(T.A, T.B) show scalar "T.B value at highest T.A" with V